HOW TO CLICK AN ITEM IN A SUBMENU (UL) LIST USING PYTHON, SELENIUM

I spent literally 3 days trying to simply click a logout link with Selenium. I searched every stackoverflow post I could find until I found this one.

I had tried pretty much everything I could to try to click the logout link which was the fifth item down in the move-over list.

I tried find_element_by_xpath, find_element_by_id, find this, find that, blah blah blah

Finally, it was indeed the find_element_by_css_selector that worked.

The only thing is I still do not know WHY the xpath option didn’t work for this list while the others did. Hmm. Whatever. Probably will figure it out later….HOW TO CLICK AN ITEM IN A SUBMENU (UL) LIST USING PYTHON, SELENIUMThe only thing is I still do not know WHY the xpath option didn’t work for this list while the others did. Hmm. Whatever. Probably will figure it out later….

so, here is a code block of what worked for me to move to a mouse-over menu and click the menu’s submenu item using Selenium and python (my css selector is just a fake example of course so paste your correct one in):

Edit: I also realized I had to click on the button *above* the actual unordered list (UL) element to trigger the drop down. This tip for the ‘main_menu’ element below might also help someone.

main_menu = driver.find_element_by_xpath("//*[@id='with-label']")

actions.move_to_element(main_menu).perform()

time.sleep(2)

WebDriverWait(driver, 10).until(EC.visibility_of_element_located((By.CSS_SELECTOR, ".css-selector-thing > ul:nth-child(2) > li:nth-child(6) > a:nth-child(1)")))

driver.find_element_by_css_selector(".css-selector-thing > ul:nth-child(2) > li:nth-child(6) > a:nth-child(1)").click()
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